document.write( "Question 193521This question is from textbook algebra and trigonometry structure and method book 2
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\n" ); document.write( "x^2+8y+4x-4=0
\n" ); document.write( "We have been using the formulas y-k=a(x-h)^2 and x-h=a(y-k)^2 I don't understand which to use here, even after completing the square and its confusing because I don't know which is which. please explain and be specific. thank you.
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Algebra.Com's Answer #145262 by jim_thompson5910(35256)\"\" \"About 
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\"x%5E2%2B8y%2B4x-4=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B4x%2B8y-4=0\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "Now we need to complete the square for the \"x\" terms.\r
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\n" ); document.write( "\n" ); document.write( "Take half of the x coefficient 4 to get 2. Square 2 to get 4.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B4x%2B4%2B8y-4=4\" Add the previous result 4 to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B4x%2B4%2B8y-4-4=0\" Subtract 4 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B4x%2B4%2B8y-8=0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%5E2%2B8y-8=0\" Factor \"x%5E2%2B4x%2B4\" to get \"%28x%2B2%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"8y-8=-%28x%2B2%29%5E2\" Subtract \"%28x%2B2%29%5E2\" from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"8%28y-1%29=-%28x%2B2%29%5E2\" Factor out the GCF 8 from the left side\r
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\n" ); document.write( "\n" ); document.write( "\"y-1=-%281%2F8%29%28x%2B2%29%5E2\" Multiply both sides by \"1%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-1=-%281%2F8%29%28x-%28-2%29%29%5E2\" Rewrite \"x%2B2\" as \"x-%28-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now the equation \"y-1=-%281%2F8%29%28x-%28-2%29%29%5E2\" is in the form \"y-k=a%28x-h%29%5E2\" where \"a=-1%2F8\", \"h=-2\" and \"k=1\"\r
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\n" ); document.write( "\n" ); document.write( "Vertex:\r
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\n" ); document.write( "\n" ); document.write( "The vertex of \"y-k=a%28x-h%29%5E2\" is (h,k). Since \"h=-2\" and \"k=1\", the vertex of \"y-1=-%281%2F8%29%28x-%28-2%29%29%5E2\" is (-2,1)\r
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\n" ); document.write( "\n" ); document.write( "Focus: \r
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\n" ); document.write( "\n" ); document.write( "First, we define \"p=1%2F%284a%29\" where the absolute value of \"p\" is the distance from the vertex to the focus. \r
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\n" ); document.write( "\n" ); document.write( "Note: the formula \"p=1%2F%284a%29\" is derived from the equation \"%28x-h%29%5E2=4p%28y-k%29\"\r
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\n" ); document.write( "\n" ); document.write( "The focus of \"y-k=a%28x-h%29%5E2\" is the point . In other words, simply add the value of \"p\" to the y coordinate of the vertex to get the focus.\r
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\n" ); document.write( "\n" ); document.write( "So let's find \"p\": \"p=1%2F%284a%29=1%2F%284%28-1%2F8%29%29=1%2F%28-1%2F2%29=-2\". So \"p=-2\"\r
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\n" ); document.write( "\n" ); document.write( "Since \"h=-2\", \"k=1\", and \"p=-2\", this means that \"k%2Bp=1-2=-1\"\r
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\n" ); document.write( "\n" ); document.write( "So the focus of the form is the point (-2,-1)\r
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\n" ); document.write( "\n" ); document.write( "The directrix of \"y-k=a%28x-h%29%5E2\" is the equation \"y=k-p\". \r
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\n" ); document.write( "\n" ); document.write( "Since \"y=k-p=1-%28-2%29=3\", this means that the directrix is \"y=3\"\r
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\n" ); document.write( "\n" ); document.write( "Axis of Symmetry:\r
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\n" ); document.write( "\n" ); document.write( "In this case, the axis of symmetry is simply the equation of the vertical line through the vertex.\r
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\n" ); document.write( "\n" ); document.write( "Since \"h=-2\", this means that the axis of symmetry is \"x=-2\"\r
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\n" ); document.write( "\n" ); document.write( "Visual Check:\r
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\n" ); document.write( "\n" ); document.write( "Graph of \"x%5E2%2B8y%2B4x-4=0\" with the vertex, focus, directrix (green) and axis of symmetry (blue)
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