document.write( "Question 193489: one invention saves 30% on fuel; a second saves 45%;a third, 25%. if you use all three inventions at once how much can you save? \n" ); document.write( "
Algebra.Com's Answer #145245 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Say you used the inventions on a tank that holds
\n" ); document.write( "\"100\" gallons of fuel. With the 1st invention,
\n" ); document.write( "you'd only use 70 gallons to go a far as you went
\n" ); document.write( "on a tankful before. Call that distance \"d\" mi
\n" ); document.write( "With the 2nd invention, you'd use 55 gallons
\n" ); document.write( "With the 3rd invention, you'd use 75 gallons
\n" ); document.write( "The fuel efficiencies are:
\n" ); document.write( "No inventions: \"d%2F100\" mi/gal
\n" ); document.write( "1st invention: \"d%2F70\" mi/gal
\n" ); document.write( "2nd invention: \"d%2F55\" mi/gal
\n" ); document.write( "3rd invention: \"d%2F75\" mi/gal
\n" ); document.write( "---------------------------------
\n" ); document.write( "These are RATES of fuel usage. I can add
\n" ); document.write( "the rates to get a combined rate
\n" ); document.write( "\"d%2F70+%2B+d%2F55+%2B+d%2F75\"
\n" ); document.write( "\"d%2A%281%2F70+%2B+1%2F55+%2B+1%2F75%29\"
\n" ); document.write( "\"d%2A%28165%2F11550+%2B+210%2F11550+%2B+154%2F11550%29\"
\n" ); document.write( "\"d%2A%28529%2F11550%29\"
\n" ); document.write( "\"d%2A.0458\"
\n" ); document.write( "\"d%2A%281%2F21.834%29\"
\n" ); document.write( "\"d%2A%281%2F70+%2B+1%2F55+%2B+1%2F75%29+=+d%2F21.834\" mi/gal
\n" ); document.write( "That's how much of the 100 gallon tank
\n" ); document.write( "you'd use to go \"d\" mi so you would
\n" ); document.write( "save \"100+-+21.834+=+78.166\" gallons
\n" ); document.write( "\"78.166%2F100\" = 78.166% saved
\n" ); document.write( "--------------------------------
\n" ); document.write( "I can check this by converting to decimals:
\n" ); document.write( "\"d%2A%281%2F70+%2B+1%2F55+%2B+1%2F75%29+=+d%2A%28.04286+%2B+.01818+%2B+.01333%29\"
\n" ); document.write( "\"d%2A.04579\"
\n" ); document.write( "\"d%2A%281%2F21.836%29\"
\n" ); document.write( "Close enough
\n" ); document.write( "
\n" );