document.write( "Question 193463: Respected sir,
\n" ); document.write( "[1] 15 litres of a mixture contains 20% alcohol and the rest water.If 3 litres od water be mixed in it,the percentage of alcohol in the new mixture will be ?
\n" ); document.write( "[2] A merchant has 50kg of sugar ,part of which he sells at 8% profit and the rest at 18% profit.He gains 14% on the whole.The quantity sold at 18% profit is ?
\n" ); document.write( "[3] A mixture of 20kg of spirit and water contains 10% water.how much water must be added to this mixture to raise the percentage of water to 25% ?
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Algebra.Com's Answer #145235 by radikrr(7)\"\" \"About 
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1) 15 l - 100%
\n" ); document.write( " x l - 20%
\n" ); document.write( "x=(15*20)/100 = 3 l mixture = 15 l+3 l = 18 l
\n" ); document.write( " P= (3 * 100)/ 18= 100 /6 = 16.66%\r
\n" ); document.write( "\n" ); document.write( "2) x+y =50
\n" ); document.write( " 8x+18y=50*14\r
\n" ); document.write( "\n" ); document.write( " x+y=50
\n" ); document.write( " 8x+18y=700
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\n" ); document.write( " 18x+18y=900
\n" ); document.write( " 8x+18y=700
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\n" ); document.write( " 10x=200 x=20kg p=(20/50)*100=40%\r
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\n" ); document.write( "\n" ); document.write( "3) 20 - 90% =18kg
\n" ); document.write( "Add x - 0% 0kg\r
\n" ); document.write( "\n" ); document.write( " 20+x - 100%
\n" ); document.write( " 18 - 75%\r
\n" ); document.write( "\n" ); document.write( " (20+x)*75= 18*100
\n" ); document.write( " x=4 kg \r
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