document.write( "Question 193397: ``Before, solving the problem, I just want to give you the heads up. It's
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document.write( "Systems of Equation: Application. I can't find the specific title to relate
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document.write( "with my story problems. My chapter in the book is Chapter Eight, Solving Systems by Substiution, Additional. Hope it helps!\r
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document.write( "*Two numbers are such that twice the first and 3 times the second is 31. When 4 times the second number is subtracted from 3 times the first number the result is 4. Find the two numbers.* \n" );
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Algebra.Com's Answer #145225 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let the first number be a and the second number, b. \n" ); document.write( "From the problem description, you can write: \n" ); document.write( "2a+3b = 31 \"...(the sum of) twice the first number and 3 times the second is 31.\" \n" ); document.write( "3a-4b = 4 \"When 4 times the second number is subtracted from 3 times the first number the result is 4.\" \n" ); document.write( "So you have a system of equations in two unknowns, a and b. \n" ); document.write( "2a+3b = 31 Multiply this equation by 4. \n" ); document.write( "3a-4b = 4 Multiply this equation by 3. \n" ); document.write( "8a+12b = 124 \n" ); document.write( "9a-12b = 12 Add these two equations. \n" ); document.write( "17a = 136 Divide both sides by 17 \n" ); document.write( "a = 8 \r \n" ); document.write( "\n" ); document.write( "2a+3b = 31 \n" ); document.write( "2(8)+3b = 31 \n" ); document.write( "16+3b = 31 Subtract 16 from both sides. \n" ); document.write( "3b = 15 Divide both sides by 3. \n" ); document.write( "b = 5. \n" ); document.write( "The two numbers are: 8 and 5 \n" ); document.write( " |