document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=193406>Question 193406</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having a problem solving the following equation in terms of logarithms. Could someone please help?    \r<BR>\n" );
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document.write( "Problem :<BR>\n" );
document.write( " 2^2x-4= 3^x-21\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145206 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I am having a problem solving the following equation in terms of logarithms. Could someone please help? <BR>\n" );
document.write( "Problem :<BR>\n" );
document.write( "2^(2x-4) = 3^(x-21)<BR>\n" );
document.write( "Take the log of both sides:<BR>\n" );
document.write( "(2x-4)log2 = (x-21)log3<BR>\n" );
document.write( "2xlog2 - 4log2 = xlog3 - 21*log3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "(2log2-log3)x = 4log(2) - 21*log(3)<BR>\n" );
document.write( "0.12494x = -8.81543<BR>\n" );
document.write( "x = -70.557281<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  <BR>\n" );
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