document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26723>Question 26723</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Its from differential calculus. <BR>\n" );
document.write( "LEt y= 5/³&#8730;(2x-5)^2\r<BR>\n" );
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document.write( "So far I got upto:<BR>\n" );
document.write( "d/dx=5(2x^2-10x+25)^(2/3)<BR>\n" );
document.write( "However, I can not continue on from there. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14516 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14516\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Its from differential calculus. <BR>\n" );
document.write( "LEt y= 5/³&#8730;(2x-5)^2 <BR>\n" );
document.write( "So far I got upto:<BR>\n" );
document.write( "d/dx=5(2x^2-10x+25)^(2/3)<BR>\n" );
document.write( "However, I can not continue on from there.<BR>\n" );
document.write( "the answer at the back on my book is:<BR>\n" );
document.write( "-20<BR>\n" );
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document.write( "3(2x-5)^(5/3) \r<BR>\n" );
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document.write( "Your Answer:<BR>\n" );
document.write( "see my working and comments on your work-----------<BR>\n" );
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document.write( "Its from differential calculus. <BR>\n" );
document.write( "LEt y= 5/³&#8730;(2x-5)^2 ..USE X^(-N)=1/(X^N)AND N th. ROOT OF X =X^(1/N)<BR>\n" );
document.write( "Y=5*(2X-5)^(-2/3)...<BR>\n" );
document.write( "DY/DX=5*(2X-5)^(-2/3-1)*2..USING DY/DX=DY/DU*DU/DX..HERE U=2X-5 AND DERIVATIVE OF X^N = N*X^(N-1)<BR>\n" );
document.write( "DY/DX=(-20/3)*(2X-5)^(-5/3)<BR>\n" );
document.write( "(-20)/3*(2X-5)^(5/3)<BR>\n" );
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document.write( "So far I got upto:<BR>\n" );
document.write( "d/dx=5(2x^2-10x+25)^(2/3)..YOU SQUARED 2X-5 ..THEN WHY AGAIN POWER OF 2/3..IT SHOULD BE ONLY 1/3..FURTHER IT SHOULD BE -1/3 AND NOT +<BR>\n" );
document.write( "However, I can not continue on from there.<BR>\n" );
document.write( "the answer at the back on my book is:<BR>\n" );
document.write( "-20<BR>\n" );
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document.write( "3(2x-5)^(5/3)<BR>\n" );
document.write( " </SPAN>\n" );
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