document.write( "Question 193335: Kelly seels 80 shares of stock she owns for a total of $491. If the stock was in two different companies, one selling at $5.50 a share and the other at $6.25 a share, how much of each did she sell?\r
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document.write( "At $5.50 \r
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document.write( "At $6.25 \n" );
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Algebra.Com's Answer #145133 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! given, total =80 shares =$491 \n" ); document.write( "let x = # shares @ $5.50 \n" ); document.write( "let y= # shares @ $6.25 \n" ); document.write( "491=5.50*x+6.25 y \n" ); document.write( "but x +y=80,,,,therefore x=(80-y)\r \n" ); document.write( "\n" ); document.write( "491 = (5.5)(80-y) + (6.25)(y) \n" ); document.write( "491= 440-5.5y+6.25y \n" ); document.write( "51=.75y \n" ); document.write( "y=68 \n" ); document.write( "and therefore x=80-68=12\r \n" ); document.write( "\n" ); document.write( "check \n" ); document.write( "491=12(5.50)+68(6.25)=66+425=491,,,,ok \n" ); document.write( " |