document.write( "Question 193316: A coffee shop decides to blend a coffee that sells for $12 per pound with a coffee that sells for $9 per pound to produce a blend that will sell for $10 per pound. How much of each should be used to yield 20 pounds of the new blend? \n" ); document.write( "
Algebra.Com's Answer #145121 by nerdybill(7384)\"\" \"About 
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A coffee shop decides to blend a coffee that sells for $12 per pound with a coffee that sells for $9 per pound to produce a blend that will sell for $10 per pound. How much of each should be used to yield 20 pounds of the new blend?
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\n" ); document.write( "Let x = pounds of $12 per pound coffee
\n" ); document.write( "then
\n" ); document.write( "20-x = pounds of $9 per pound coffee
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\n" ); document.write( "12x + 9(20-x) = 10(20)
\n" ); document.write( "12x + 180 - 9x = 200
\n" ); document.write( "3x + 180 = 200
\n" ); document.write( "3x = 20
\n" ); document.write( "x = 20/3
\n" ); document.write( "x = 6 and 2/3 pounds of $12 per pound coffee
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\n" ); document.write( "Amount of $9 per pound coffee:
\n" ); document.write( "20-x = 20-20/3 = 60/3 - 20/3 = 40/3
\n" ); document.write( "or
\n" ); document.write( "13 and 1/3 pounds of $9 per pound coffee \n" ); document.write( "
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