document.write( "Question 26732: I can't figure out how to set this problem up. \"One type of antifreeze is 40% gylcol and another type of antifreeze is 60% gylcol. How much of each kind should be used to make 100 gallons of antifreeze that is 48% glycol.\" Help please. Thanks. \n" ); document.write( "
Algebra.Com's Answer #14512 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! 40x+60(100-x)=48(100) \n" ); document.write( "40x+6000-60x=4800 \n" ); document.write( "-20x=-1200 \n" ); document.write( "x=60\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "100-60=40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "hence, for 40% about 60 G is used and for 60% about 40 G is used. \n" ); document.write( "Paul. \n" ); document.write( " |