document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=193254>Question 193254</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0138142254/algebrahomeworkh>Basic Technical Mathematics</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I am totally confused with this word problem about exectric current i in a circuit containing a resistance R and an inductance L given by ln i/I=Rt/L. t is the time (in seconds) and I is the current at t=0. Calculate in seconds it take the current to reach 0.600 of the initial value if I=0.584A, R=7.44 olms and L=1.41H.<BR>\n" );
document.write( "Please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145102 by </B><A HREF=/tutors/aboutme.mpl?userid=ejazali_syed><B>ejazali_syed(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ejazali_syed><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145102\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ln i/I=Rt/L\r<BR>\n" );
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document.write( "FIrst of all i didnt get this point (the current to reach 0.600 of the initial value, but still im considering it to be 0.6 of initial value)\r<BR>\n" );
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document.write( "Calculate in seconds it take the current to reach 0.600 of the initial value if I=0.584A, R=7.44 ohms and L=1.41H.\r<BR>\n" );
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document.write( "ANS) i here is the current.<BR>\n" );
document.write( "I is the current at time t= 0.<BR>\n" );
document.write( "we need to calculate the time in \"seconds\" <BR>\n" );
document.write( "         when????<BR>\n" );
document.write( "         when current reaches 0.600 i.e. i = 0.6 of the initial value.<BR>\n" );
document.write( "        <BR>\n" );
document.write( "            what is the initial value given I = 0.584A\r<BR>\n" );
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document.write( "             hence i = 0.6 of I = 0.6*0.584 = 0.3054A\r<BR>\n" );
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document.write( "therefore\r<BR>\n" );
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document.write( "ln(i/I) = R*t/L   ==>    ln(0.6*I/I) = 7.44*t/1.41   \r<BR>\n" );
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document.write( "      ==>   ln(0.6)* 0.1895 = t (in seconds) </SPAN>\n" );
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