document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=191272>Question 191272</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 220 inches. THe lenght exceeds the width by 40 Inches. What is the lenght and the width?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145101 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10553)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145101\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width of the rectangle be w<BR>\n" );
document.write( "Then the length of the rectangle is w + 40\r<BR>\n" );
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document.write( "Then, 2w  +  2(w + 40)  =  220<BR>\n" );
document.write( "2w + 2w + 80 = 220<BR>\n" );
document.write( "4w  =  140<BR>\n" );
document.write( "w   =  35\r<BR>\n" );
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document.write( "Therefore, width = 35, and length = 75 (35 + 40).\r<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "220 (perimeter) =  2(35) + 2(35 + 40) <BR>\n" );
document.write( "220  =  70  +  150 (True)<BR>\n" );
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