document.write( "Question 193097: Draw three different nonconvex polygons. When you walk around a polygon, at each vertex you need to turn either right (clockwise) or left (counterclockwise). A turn to the left is measured by a positive number of degrees and a turn to the right by a negative number of degrees. Find the sum of the measures of the turn angles of the polygons you drew. Assume you start at a vertex facing in the direction of a side, walk around the polygon, and end up at the same vertex facing in the same direction as when you started.\r
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document.write( "please I need help I dont think you have to draw this I believe it is 360degrees
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document.write( "But I am not ure how to explain how i came up with it.\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #145092 by RAY100(1637) ![]() You can put this solution on YOUR website! You are right about sum of exterior angles = 360 always. \n" ); document.write( " a rough sketch is perhaps best way to explain external angles \n" ); document.write( "draw a point,,,,and just a quadrilateral for example \n" ); document.write( "pick one vertex of quadrilateral,,,, on point draw exterior angle to match. \n" ); document.write( "go to next vertex,,,,draw that exterior angle on point sketch,,,(one side should match previous angle) \n" ); document.write( "go to next vertex,,, draw that ext angle on point drawing \n" ); document.write( "if you progress around quadrilateral,,,and mark only ext angles on point dwg,, \n" ); document.write( "you should get back to beginning,, \n" ); document.write( "on a point drawing if we rotate around once and come back to beginning, we go 360 degrees \n" ); document.write( "the number of sides does not matter, nor does any + or - rotations, because we always go around once, and come back to beginning. \n" ); document.write( " |