document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=193142>Question 193142</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me with this linear equation?<BR>\n" );
document.write( " An administrator of a popular website is told that a new faster server, can handle 45,000 \"hit\" (users accessing the site)per second.  The web site currently experience a peak demand of about 110,000 hits per second. But, every month, the peak demand increases by 2500 hits per second. Use proportion equation to determine how many new servers the administrator should buy to address expected traffic for the next 24 months. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #145088 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=145088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> good  problem\r<BR>\n" );
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document.write( "increasing  demand  is  an  arithmetic  sequence<BR>\n" );
document.write( "H=110,000+(n-1)*2500<BR>\n" );
document.write( "H(24)= 110,000+23*2500=110,000+57500=167,500\r<BR>\n" );
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document.write( "proportion  of  required  machines  to  fit  capacity<BR>\n" );
document.write( "1/45,000=x/167,500<BR>\n" );
document.write( "cross  multiply\r<BR>\n" );
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document.write( "167,500=45,000x<BR>\n" );
document.write( "x=3.7  or  4  machines </SPAN>\n" );
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