document.write( "Question 193252: if $350 is deposited in an account paying 2% annual interest, compunded continuously, how long will it take for the account to increase to $1500?\r
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\n" ); document.write( "\n" ); document.write( "A=Pe^rt\r
\n" ); document.write( "\n" ); document.write( "1500=350e^.02(t)\r
\n" ); document.write( "\n" ); document.write( "then im lost...
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Algebra.Com's Answer #145084 by MathGuyJoe(20)\"\" \"About 
You can put this solution on YOUR website!
To Solve: \"1500=350e%5E%28.02t%29\"\r
\n" ); document.write( "\n" ); document.write( "You must first isolate the e^x component -- so divide both sides by 350:\r
\n" ); document.write( "\n" ); document.write( "\"+1500+%2F+350+=+e%5E%28.02t%29+\"\r
\n" ); document.write( "\n" ); document.write( "Simplifying gives you:\r
\n" ); document.write( "\n" ); document.write( "\"+30+%2F+7+=+e%5E%28.02t%29+\"\r
\n" ); document.write( "\n" ); document.write( "Next, take the natural log (ln) of both sides:\r
\n" ); document.write( "\n" ); document.write( "\"+ln%2830%2F7%29+=+ln%28e%5E%28.02t%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "Now, use the power rule \"+ln%28x%29%5En+=+n+%2A+ln%28x%29+\" to simplify the right side:\r
\n" ); document.write( "\n" ); document.write( "\"+ln%2830%2F7%29+=+.02t%2Aln%28e%29+\"\r
\n" ); document.write( "\n" ); document.write( "Since \"+ln%28e%29+=+1+\", you're left with:\r
\n" ); document.write( "\n" ); document.write( "\"+ln%2830%2F7%29+=+.02t+\"\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by .02 to get:\r
\n" ); document.write( "\n" ); document.write( "\"+%28ln%2830%2F7%29%2F.02%29+=+t+\"\r
\n" ); document.write( "\n" ); document.write( "So t = 72.76 years
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\n" ); document.write( "Hope this helps.
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\n" ); document.write( "~ Joe
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