document.write( "Question 193166: sqrt(4x-5)=sqrt(x+9)\r
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Algebra.Com's Answer #145006 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%284x-5%29=sqrt%28x%2B9%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"%28sqrt%284x-5%29%29%5E2=%28sqrt%28x%2B9%29%29%5E2\" Square both sides\r
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\n" ); document.write( "\n" ); document.write( "\"4x-5=x%2B9\" Square the square roots to eliminate them\r
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\n" ); document.write( "\n" ); document.write( "\"4x=x%2B9%2B5\" Add \"5\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"4x-x=9%2B5\" Subtract \"x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"3x=9%2B5\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"3x=14\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2814%29%2F%283%29\" Divide both sides by \"3\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=14%2F3\" which approximates to \"x=4.667\".
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