document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=193147>Question 193147</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One dimension of a cube is increased by 1, another is decreased by 1, and the third is left unchanged. The volume of the new rectangular solid is 5 less than that of the cube. What is the volume of the cube?\r<BR>\n" );
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document.write( "Please explain how to solve this problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144987 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the dimension of one side of the original cube.  Its volume is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V%5Bc%5D+=+x%5E3 ALIGN=MIDDLE  ALT=\"V%5Bc%5D+=+x%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The three sides of the new solid are: x, (x-1), and (x+1).<BR>\n" );
document.write( "The volume of the new solid is:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V%5Bn%5D+=+%28x%29%28x-1%29%28x%2B1%29 ALIGN=MIDDLE  ALT=\"V%5Bn%5D+=+%28x%29%28x-1%29%28x%2B1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V%5Bn%5D+=+x%5E3-x ALIGN=MIDDLE  ALT=\"V%5Bn%5D+=+x%5E3-x\"   DISABLED_style= \"max-width:90%; height:auto;\" > and this is said to be equal to five less than that of the cube, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E3-5 ALIGN=MIDDLE  ALT=\"x%5E3-5\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so....<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E3-x+=+x%5E3-5 ALIGN=MIDDLE  ALT=\"x%5E3-x+=+x%5E3-5\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E3 ALIGN=MIDDLE  ALT=\"x%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" > from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-x+=+-5 ALIGN=MIDDLE  ALT=\"-x+=+-5\"   DISABLED_style= \"max-width:90%; height:auto;\" > or<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+5 ALIGN=MIDDLE  ALT=\"x+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The volume of the cube is then...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V%5Bc%5D+=+x%5E3 ALIGN=MIDDLE  ALT=\"V%5Bc%5D+=+x%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" > substitute x = 5.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V%5Bc%5D+=+5%5E3 ALIGN=MIDDLE  ALT=\"V%5Bc%5D+=+5%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28V%5Bc%5D+=+125%29 ALIGN=MIDDLE  ALT=\"highlight%28V%5Bc%5D+=+125%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > cubic units. </SPAN>\n" );
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