document.write( "Question 193054: Perimeter of a rectangle is 32 inches, area of the rectangle is 60 square inches. What is the length and width? \n" ); document.write( "
Algebra.Com's Answer #144982 by jonvaliente(64)\"\" \"About 
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Perimeter=2*L + 2*W
\n" ); document.write( "Area = L*W
\n" ); document.write( "Let L=length and W=width of your rectangle\r
\n" ); document.write( "\n" ); document.write( "If Perimeter=32, then
\n" ); document.write( "2*L+2*W=32 (1)
\n" ); document.write( "If Area=60, then
\n" ); document.write( "L*W=60 (2)
\n" ); document.write( "Let's take (1), and express L in terms of W:
\n" ); document.write( "2L + 2W = 32
\n" ); document.write( "L + W = 16 (divide bot sides by 2)
\n" ); document.write( "L = 16-W (subtract W from both sides)
\n" ); document.write( "We can now substitute this value of L in (2), so:
\n" ); document.write( "\"%2816-W%29%2AW=60\"
\n" ); document.write( "\"16W-W%5E2=60\" (Simplifying)
\n" ); document.write( "\"W%5E2-16W%2B60=0\" (Add W^2-16W on both sides)
\n" ); document.write( "\"%28W-6%29%28W-10%29=0\" (Factoring)
\n" ); document.write( "If we take W-6=0,
\n" ); document.write( "W=6 and L=16-W=16-6=10 inches, so our rectangle is 6 inches wide and 10 inches long
\n" ); document.write( "If we take W-10=0
\n" ); document.write( "W=10 and L=16-10=6 inches, but generally length is longer than width so we just take the first solution.\r
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