document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=193136>Question 193136</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I got x=log9 (1/81)\r<BR>\n" );
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document.write( "I have tried it this way:\r<BR>\n" );
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document.write( "log9 1 - log9 3^4 = \r<BR>\n" );
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document.write( "log9 1 - 4log9 3 = \r<BR>\n" );
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document.write( "but the task does not only state log9 (1/81) it says x=...\r<BR>\n" );
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document.write( "so i am not sure if I am going the correct way!<BR>\n" );
document.write( "could you help me on this one? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144981 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144981\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=log9 (1/81) <BR>\n" );
document.write( "x = log9(1) - log9(81)<BR>\n" );
document.write( "Since it is \"base 9\", write in terms of powers of 9:<BR>\n" );
document.write( "x = log9(9^0) - log9(9^2)<BR>\n" );
document.write( "x = 0 - 2<BR>\n" );
document.write( "x = -2<BR>\n" );
document.write( " </SPAN>\n" );
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