document.write( "Question 193131: An express and local train leave GraysLake at 3 P.M and head for Chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train. \n" ); document.write( "
Algebra.Com's Answer #144980 by jonvaliente(64)\"\" \"About 
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Let x=no of hours it takes for the local train
\n" ); document.write( "x-1=no of hours it takes for the express train
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\n" ); document.write( "Since speed=distance/time,
\n" ); document.write( "speed of the local train = 50/x
\n" ); document.write( "speed of the express train =50/(x-1)
\n" ); document.write( "If the express train is twice as fast as the local train then:
\n" ); document.write( "\"2%2A%2850%2Fx%29=50%2F%28x-1%29\"
\n" ); document.write( "\"100%2Fx=50%2F%28x-1%29\"
\n" ); document.write( "Multiplying both sides by x*(x-1), we get:
\n" ); document.write( "\"100%2A%28x-1%29=50%2Ax\"
\n" ); document.write( "\"100x-100=50x\"
\n" ); document.write( "Subtracting 50x from both sides, we get:
\n" ); document.write( "\"50x-100=0\"
\n" ); document.write( "Adding 100 on both sides, we get:
\n" ); document.write( "\"50x=100\"
\n" ); document.write( "Diving both sides by 50 we get:
\n" ); document.write( "x=2
\n" ); document.write( "So, the local train takes 2 hours to get to Chicago and the express only takes 1 hour to get there.
\n" ); document.write( "speed of the local train = 50/2 = 25 mph
\n" ); document.write( "speed of the express train = 50/1 = 50 mph\r
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