document.write( "Question 193131: An express and local train leave GraysLake at 3 P.M and head for Chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train. \n" ); document.write( "
Algebra.Com's Answer #144980 by jonvaliente(64)![]() ![]() You can put this solution on YOUR website! Let x=no of hours it takes for the local train \n" ); document.write( "x-1=no of hours it takes for the express train \n" ); document.write( ". \n" ); document.write( "Since speed=distance/time, \n" ); document.write( "speed of the local train = 50/x \n" ); document.write( "speed of the express train =50/(x-1) \n" ); document.write( "If the express train is twice as fast as the local train then: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Multiplying both sides by x*(x-1), we get: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Subtracting 50x from both sides, we get: \n" ); document.write( " \n" ); document.write( "Adding 100 on both sides, we get: \n" ); document.write( " \n" ); document.write( "Diving both sides by 50 we get: \n" ); document.write( "x=2 \n" ); document.write( "So, the local train takes 2 hours to get to Chicago and the express only takes 1 hour to get there. \n" ); document.write( "speed of the local train = 50/2 = 25 mph \n" ); document.write( "speed of the express train = 50/1 = 50 mph\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |