document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26651>Question 26651</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation log^9(3x+14)-log^95=log^92x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14498 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14498\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log^9(3x+14)-log^95=log^92x.<BR>\n" );
document.write( "i think you mean all logs are to base 9...in that case since all are to a common base we can drop the base.<BR>\n" );
document.write( "log(3x+1)-log 5=log(2x)....or.....log(3x+1)-log 5-log(2x)=0<BR>\n" );
document.write( "log{(3x+1)/(5*2x)=0..taking antilogs,we get <BR>\n" );
document.write( "(3x+1)/10x=1<BR>\n" );
document.write( "3x+1=10x...or...10x-3x=1...<BR>\n" );
document.write( "7x=1<BR>\n" );
document.write( "x=1/7 </SPAN>\n" );
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