document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=193102>Question 193102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular picture frame is 4 times as wide as its length with a perimeter of 80 inches. Find the dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144977 by </B><A HREF=/tutors/aboutme.mpl?userid=orca><B>orca(409)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=orca><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144977\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the length.<BR>\n" );
document.write( "Then its width 4x<BR>\n" );
document.write( "So the perimeter in terms of x is 2(x + 4x)<BR>\n" );
document.write( "Setting it equal to 80, we have<BR>\n" );
document.write( "2(x + 4x) = 80<BR>\n" );
document.write( "Solving for x, we have<BR>\n" );
document.write( "2*5x = 80<BR>\n" );
document.write( "10x = 80<BR>\n" );
document.write( "x = 8<BR>\n" );
document.write( "Therefore the length is 8<BR>\n" );
document.write( "the width is 4x = 4*8 = 32<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );