document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=193092>Question 193092</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618503080/algebrahomeworkh>Intermediate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A plane leaves an airport at 3:00 PM.  At 4:00 PM another plane leaves the same airport traveling in the same direction at a speed 150 mph faster than that of the first plane.  Four hours after the first planes takes off, the second plane is 250 mi ahead of the first plane.  How far does the second plane travel? \r<BR>\n" );
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document.write( "my try: <BR>\n" );
document.write( "4x + 4(x+150) =250 <BR>\n" );
document.write( "4x + 4x + 600 = 250<BR>\n" );
document.write( "8x + 600 = 250<BR>\n" );
document.write( "8x = 350<BR>\n" );
document.write( "x = 350/8<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144936 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A plane leaves an airport at 3:00 PM. At 4:00 PM another plane leaves the same airport traveling in the same direction at a speed 150 mph faster than that of the first plane. Four hours after the first planes takes off, the second plane is 250 mi ahead of the first plane. How far does the second plane travel? <BR>\n" );
document.write( "my try: <BR>\n" );
document.write( "4x + 4(x+150) =250 <BR>\n" );
document.write( "4x + 4x + 600 = 250<BR>\n" );
document.write( "8x + 600 = 250<BR>\n" );
document.write( "8x = 350<BR>\n" );
document.write( "x = 350/8<BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "Going in the same direction, the speed relative to each other is the difference, not the sum.<BR>\n" );
document.write( "x is the speed of the slower plane.  It flies 4 hrs at x = 4x miles.<BR>\n" );
document.write( "x+150 is the speed of the faster plane.  It flies 3 hrs at x+150.<BR>\n" );
document.write( "3(x+150) = 4x + 250<BR>\n" );
document.write( "3x+450 = 4x + 250<BR>\n" );
document.write( "x = 200 mph<BR>\n" );
document.write( "The faster plane goes 350 mph for 3 hours, so the distance is <BR>\n" );
document.write( "1050 miles.\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );