document.write( "Question 193082: the task is 3/7 = 2/x-4\r
\n" ); document.write( "\n" ); document.write( "i solved as follows: 0=(2/x-4)/(3/7) = 2/(x-4)*(7/3) now the result would be 14/3x-12 but I know that this is the wrong answer... where is my mistake?
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Algebra.Com's Answer #144925 by Alan3354(69443)\"\" \"About 
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the task is 3/7 = 2/x-4
\n" ); document.write( "i solved as follows: 0=(2/x-4)/(3/7) = 2/(x-4)*(7/3) now the result would be 14/3x-12 but I know that this is the wrong answer... where is my mistake?
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\n" ); document.write( "You divided by (3/7), which makes it = 1, not zero.
\n" ); document.write( "3/7 = 2/x-4
\n" ); document.write( "Cross multiply
\n" ); document.write( "3*(x-4) = 14
\n" ); document.write( "3x-12 = 14
\n" ); document.write( "3x = 26
\n" ); document.write( "x = 26/3
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