document.write( "Question 26578: This seems like a simple problem... however, I'm trying to learn the core reason on how and why this problem works. (I got the answer from the back of my math book, but I want to understand it.)\r
\n" ); document.write( "\n" ); document.write( "b-a^(-1) / a-b^(-1)\r
\n" ); document.write( "\n" ); document.write( "Thanks.
\n" ); document.write( "

Algebra.Com's Answer #14492 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
you do not say whether your powers apply to all the terms or just the second in each pair?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x%29%5E%28-2%29\" is 1/(x)^2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "so, \"%28b-a%29%5E-1%29\" is 1/(b-a)
\n" ); document.write( "Similarly \"%28a-b%29%5E-1%29\" is 1/(a-b)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "so \"%28b-a%29%5E%28-1%29%2F%28a-b%29%5E%28-1%29\" becomes \"%281%2F%28b-a%29%29%2F%281%2F%28a-b%29%29\" which is
\n" ); document.write( "\"%28a-b%29%2F%28b-a%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "jon.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );