document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=193050>Question 193050</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the area of a circle with circumference of 18 pi centimeters?  Give your answer in terms of pi.  i think i should refer to theorem 11-7 and 11-8.  i cannot show you what work i have done on this because my keyoard does not have a symbol for pi.  thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144892 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144892\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Very  typical  problem<BR>\n" );
document.write( "remember  Cir=2(pi)R,,,,and  Area  =  (pi)  r^2<BR>\n" );
document.write( "by  finding  r,  the  problem  becomes  easy<BR>\n" );
document.write( "given  cir  so  lets  start  there<BR>\n" );
document.write( "c=2(pi)r=18(pi)<BR>\n" );
document.write( "or 2*r=18<BR>\n" );
document.write( "r=9\r<BR>\n" );
document.write( "\n" );
document.write( "Area  = (pi) r^2=(pi) 9^2=81(pi) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );