document.write( "Question 193039: How do you solve:(y+1)(y-3)(y-4)? Also:(x+1)(x+1)(x+1)? Using the FOIL and then the vertical methods? \n" ); document.write( "
Algebra.Com's Answer #144891 by RAY100(1637)\"\" \"About 
You can put this solution on YOUR website!
exactly right\r
\n" ); document.write( "\n" ); document.write( "lets review
\n" ); document.write( "(y+1)(y-3)(y-4)
\n" ); document.write( "foil ist 2 terms
\n" ); document.write( "(y^2 -3y+y-3)(y-4)
\n" ); document.write( "(y^2-2y-3)(y-4)
\n" ); document.write( "rearrange, commutative property
\n" ); document.write( "(y-4)(y^2-2y-3)
\n" ); document.write( "now use distribution
\n" ); document.write( "(y)(y^2-2y-3) - (4)(y^2-2y-3)
\n" ); document.write( "y^3-2y^2-3y -4y^2+8y+12
\n" ); document.write( "combine like terms
\n" ); document.write( "y^3-6y^2+5y+12 ANSWER
\n" ); document.write( "Yes we prefer vertical allignment, but extremely hard to type
\n" ); document.write( "check let y=0,,,original 1*-3*-4=12
\n" ); document.write( "answer,,,,12=12 ok
\n" ); document.write( "check again with y=1
\n" ); document.write( "original,,,2*-2*-3=12
\n" ); document.write( "answer,,,,1-6+5+12=12 ok\r
\n" ); document.write( "\n" ); document.write( "again, with practice this moves right along
\n" ); document.write( "(x+1)(x+1)(x+1)
\n" ); document.write( "(x+1)(x^2+2x+1)
\n" ); document.write( "x(x^2+2x+1)+1(x^2+2x+1)
\n" ); document.write( "x^3 +2x^2+x +x^2+2x+1
\n" ); document.write( "x^3 +3x^2+3x+1 ANSWER
\n" ); document.write( "check using y=0
\n" ); document.write( "0riginal ,,,1 answer,,,1,,,,ok
\n" ); document.write( "with y=2
\n" ); document.write( "answer,,,27,,,answer8+12+6+1=27\r
\n" ); document.write( "\n" ); document.write( "KEEP UP the good work,,,,it just takes a little practice
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