document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192976>Question 192976</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm not sure if this question has been asked before, but I'm having trouble with two different rational functions. I would really like to learn how to solve them. \r<BR>\n" );
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document.write( "1.) 5x / x^2 - 25 = 2 / x - 5\r<BR>\n" );
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document.write( "2.) 1 + 2 / x = 3 / x^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144857 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144857\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.) 5x / (x^2 - 25) = 2 / (x - 5)\r<BR>\n" );
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document.write( "lcm = x^2-25 = (x+5)(x-5)<BR>\n" );
document.write( "Multiply both sides by the lcm to get:<BR>\n" );
document.write( "5x = 2(x+5)<BR>\n" );
document.write( "5x = 2x+10<BR>\n" );
document.write( "3x = 10<BR>\n" );
document.write( "x = 10/3<BR>\n" );
document.write( "-------------------\r<BR>\n" );
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document.write( "2.) 1 + (2 / x) = (3 / x^2)<BR>\n" );
document.write( "Multiply thru by x^2 to get:<BR>\n" );
document.write( "x^2 + 2x = 3<BR>\n" );
document.write( "x^2 + 2x - 3 = 0<BR>\n" );
document.write( "(x+3)(x-1) = 0<BR>\n" );
document.write( "x = 1 or x = -3<BR>\n" );
document.write( "----------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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