document.write( "Question 192974: I need help with a few problems. I am stuck.\r
\n" ); document.write( "\n" ); document.write( "1) Write the equation (1/5)^-7 = 78125 in logarithmic form.\r
\n" ); document.write( "\n" ); document.write( "2) Simplify the expression (256x^4y)^1/4/(81xy^3)^3/4 Assume that all variables represent positive numbers\r
\n" ); document.write( "\n" ); document.write( "3) Find the value of x: log 3 27 = x\r
\n" ); document.write( "\n" ); document.write( "4) Assume that all variables are positive and multiply y^2/6(y^-2/6 + 8y^4/6)\r
\n" ); document.write( "\n" ); document.write( "Any and all help will be appreciated.\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance!!
\n" ); document.write( "

Algebra.Com's Answer #144840 by RAY100(1637)\"\" \"About 
You can put this solution on YOUR website!
1)(1/5)^-7=78125
\n" ); document.write( "(5/1)^7=78125
\n" ); document.write( "5^7=78125 ok\r
\n" ); document.write( "\n" ); document.write( "log to base 5 of 78125=7\r
\n" ); document.write( "\n" ); document.write( "checklog78126/log5=7 ok\r
\n" ); document.write( "\n" ); document.write( "2) ( (256x^4y)^(1/4))/( (81xy^3)^(3/4))
\n" ); document.write( "num
\n" ); document.write( "256^.25=4
\n" ); document.write( "(x^4)^.25=x^1=x
\n" ); document.write( "den
\n" ); document.write( "81^(3/4)= (81^.25)^3=3^3=27
\n" ); document.write( "(y^3)^(3/4)=(y^(9/4)
\n" ); document.write( "combining
\n" ); document.write( "( 4*x*y^.25)/ ( 27*x^.75*y^(9/4))
\n" ); document.write( "remember to divide common bases,, subst exponents
\n" ); document.write( "(4x^.250/(27y^2)\r
\n" ); document.write( "\n" ); document.write( "check, let x=2, y=3
\n" ); document.write( "answer (4*2^.25)/(27*3^2) =.01957
\n" ); document.write( "original ((256*2^4*3)^.25)/( ( 81*2*3^3)^.75)
\n" ); document.write( "10.5286/537.85 = .0196 ok\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "3) log base 3 of 27 = x
\n" ); document.write( "log27/log3=3=x\r
\n" ); document.write( "\n" ); document.write( "check 3^3=27 ok\r
\n" ); document.write( "\n" ); document.write( "4) (y^(2/6))*(y^(-2/6)+8y^(4/6))
\n" ); document.write( "y^(2/6-2/6) +8 y^(2/6+4/6)
\n" ); document.write( "Y^0 +8y^1
\n" ); document.write( "1+8y
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