document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192971>Question 192971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars start from the same point and ride in opposite directions. One car travels 30 mph slower than the other car. in six hours they are 600 miles apart. what is the rate of each car?  D=rt </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144831 by </B><A HREF=/tutors/aboutme.mpl?userid=bhayzone><B>bhayzone(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bhayzone><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let,<BR>\n" );
document.write( "r = rate of the slower driver.<BR>\n" );
document.write( "r+30 = rate of faster driver.\r<BR>\n" );
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document.write( "In 6 hours,<BR>\n" );
document.write( "Slower driver drives 6*r miles (dist = rate*time)<BR>\n" );
document.write( "Faster driver drives 6*(r+30)\r<BR>\n" );
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document.write( "Totally between them they driver 600 miles.<BR>\n" );
document.write( "Thus,<BR>\n" );
document.write( "6*r + 6*(r+30)=600<BR>\n" );
document.write( "Solving for r, we get<BR>\n" );
document.write( "r (slover drivers rate) = 35 mph<BR>\n" );
document.write( "r+30 (faster driver rate)= 65mph<BR>\n" );
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