document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192973>Question 192973</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles of a triange have the same measure and the third angle is 30 degrees greater than the other two. Find the measures of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144830 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144830\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> remember  the  sum  if  angles  of  a  triangle  =180 deg\r<BR>\n" );
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document.write( "gives  angles  of,, x,x,(x+30)\r<BR>\n" );
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document.write( "sum  =  3x +30=180<BR>\n" );
document.write( "subt  30  both  sides<BR>\n" );
document.write( "3x=180-30=150<BR>\n" );
document.write( "divide  both  sides  by  3<BR>\n" );
document.write( "x=50\r<BR>\n" );
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document.write( "answer,  sides  of  50,50,80\r<BR>\n" );
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document.write( "check  50+50+80=180  ok\r<BR>\n" );
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document.write( "80-50=30  ok </SPAN>\n" );
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