document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192971>Question 192971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars start from the same point and ride in opposite directions. One car travels 30 mph slower than the other car. in six hours they are 600 miles apart. what is the rate of each car?  D=rt </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144828 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144828\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let  rate  of  one  car  be  x,  rate  of  other  is  (x-30)<BR>\n" );
document.write( "given  t=6<BR>\n" );
document.write( "given  d=600  at t=6\r<BR>\n" );
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document.write( "d1 = x*6<BR>\n" );
document.write( "d2 =(x-30)*6\r<BR>\n" );
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document.write( "D1+D2=600=x*6+(x-30)*6=6(2x-30)<BR>\n" );
document.write( "divive  both  sides  by  6<BR>\n" );
document.write( "100=(2x-30)<BR>\n" );
document.write( "add  30  both  sides<BR>\n" );
document.write( "130=2x<BR>\n" );
document.write( "divide  both  sides  by 2<BR>\n" );
document.write( "65=x<BR>\n" );
document.write( "(x-30)=35\r<BR>\n" );
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document.write( "checking<BR>\n" );
document.write( "65-35=30  ok\r<BR>\n" );
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document.write( "(65 +35) 6=100*6=600  ok </SPAN>\n" );
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