document.write( "Question 26641: Please could you help with this equation\r
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document.write( "Solve the following equation for x ( 3coshx + 5sinhx = 8)\r
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document.write( "I've this far but can't finish the rest\r
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document.write( "3coshx + 5sinhx = 8\r
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document.write( "3[ex+/-x]/2+5[ex-e-n] = 8\r
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document.write( "1.5 [ex+-x]+2.5[ex-e-x] = 8\r
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document.write( "1.5ex+1.5ex+2.5ex-2.5e-x = 8\r
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document.write( "4ex-1x = 8\r
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document.write( "4(ex)2 – 8ex-1 = 0
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Algebra.Com's Answer #14482 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! 3coshx + 5sinhx = 8 \n" ); document.write( "FOR SIMPLICITY LET US DENOTE ....E^X=A...SO ...E^(-X)=1/A...HENCE \n" ); document.write( "COSH X = (A+1/A)/2...AND .....SINH X=(A-1/A)/2...SO WE HAVE \n" ); document.write( "3(A+1/A)/2+5(A-1/A)/2=8...MULTIPLYING BY 2 \n" ); document.write( "3A+3/A+5A-5/A=16 \n" ); document.write( "8A-2/A=16.....DIVIDING BY 2 WE GET \n" ); document.write( "4A-1/A-8=0....OR MULTIPLYING BY A... \n" ); document.write( "4A^2-8A-1=0 \n" ); document.write( "USING QUADRATIC FORMULA.. \n" ); document.write( "WE GET .. \n" ); document.write( ".. \n" ); document.write( ".. \n" ); document.write( ".. \n" ); document.write( "X=LN{1+0.5(0.5)^(0.5)} \n" ); document.write( " \n" ); document.write( " |