document.write( "Question 192729: Jim drives from the Twin Cities to Monroe Louisiana, a distance of 1075 miles in record time. On the way back he averages 5 mph slower and the trip takes an additional 1.5 hrs. How fast did he drive to Monroe LA.? Round to the nearest tenth of a mph. \n" ); document.write( "
Algebra.Com's Answer #144817 by ankor@dixie-net.com(22740)\"\" \"About 
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Jim drives from the Twin Cities to Monroe Louisiana, a distance of 1075 miles
\n" ); document.write( " in record time. On the way back he averages 5 mph slower and the trip takes
\n" ); document.write( " an additional 1.5 hrs. How fast did he drive to Monroe LA.?
\n" ); document.write( " Round to the nearest tenth of a mph.
\n" ); document.write( ":
\n" ); document.write( "let s = his original speed to La
\n" ); document.write( "then
\n" ); document.write( "(s-5) = his return speed
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\n" ); document.write( "Write a time equation: Time = \"dist%2Fspeed\"
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\n" ); document.write( "Time to + 1.5 hr = time to return
\n" ); document.write( "\"1075%2Fs\" + 1.5 = \"1075%2F%28%28s-5%29%29\"
\n" ); document.write( "Multiply equation by s(s-5), results
\n" ); document.write( "1075(s-5) + 1.5s(s-5) = 1075s
\n" ); document.write( ":
\n" ); document.write( "1075s - 5375 + 1.5s^2 - 7.5s - 1075s = 0
\n" ); document.write( ":
\n" ); document.write( "1.5s^2 - 7.5s - 5375 = 0
\n" ); document.write( ":
\n" ); document.write( "A quadratic equation, use the quadratic formula:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "In this equation: x = s; a = 1.5, b = -7.5, c = -5375
\n" ); document.write( "\"s+=+%28-%28-7.5%29+%2B-+sqrt%28-7.5%5E2+-+4+%2A+1.5+%2A+-5375+%29%29%2F%282%2A1.5%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"s+=+%287.5+%2B-+sqrt%2856.25+-+%28-32250%29+%29%29%2F%283%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"s+=+%287.5+%2B-+sqrt%2856.25+%2B+32250+%29%29%2F%283%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"s+=+%287.5+%2B-+sqrt%2832306.25+%29%29%2F%283%29+\"
\n" ); document.write( "Two solutions but we only want the positive one:
\n" ); document.write( "\"s+=+%287.5+%2B+179.74%29%2F%283%29+\"
\n" ); document.write( "\"s+=+187.24%2F3+\"
\n" ); document.write( "s = 62.4 mph to Monroe La
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\n" ); document.write( "Check solution by finding the time for each trip; return speed: 62.4 - 5 = 57.4
\n" ); document.write( "1075/57.4 = 18.73 hrs
\n" ); document.write( "1075/62.4 = 17.23 hrs
\n" ); document.write( "-----------------------
\n" ); document.write( "difference: 1.5 hrs
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