document.write( "Question 192963: in a circle whose diameter is 20 inches, a chord is 6 inches from the center. what is the length of the cord? \n" ); document.write( "
Algebra.Com's Answer #144816 by RAY100(1637)\"\" \"About 
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a rough sketch might help\r
\n" ); document.write( "\n" ); document.write( "from center of circle draw a horizontal line to circle perimeter
\n" ); document.write( "about half way out draw a perpendicular chord.
\n" ); document.write( "from center to point on circle that chord intersects draw the last line. This is a radius and the length is 10.\r
\n" ); document.write( "\n" ); document.write( "the triangle constructed is a right triangle, since it bisects a chord.\r
\n" ); document.write( "\n" ); document.write( "let x be distance from center of the circle to intersection of chord. This is given to be 6\r
\n" ); document.write( "\n" ); document.write( "pythagorous is a good tool for rt triangles. In our case one leg is 6, and the hypotenuse is 10.\r
\n" ); document.write( "\n" ); document.write( "c^2=a^2+b^2
\n" ); document.write( "10^2 =6^2 +b^2
\n" ); document.write( "100-36=64=b^2
\n" ); document.write( "or b=8\r
\n" ); document.write( "\n" ); document.write( "chord total length is 2b, or 16\r
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