document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192963>Question 192963</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in a circle whose diameter is 20 inches, a chord is 6 inches from the center. what is the length of the cord? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144814 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144814\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, draw a picture\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src=\"http://i150.photobucket.com/albums/s91/jim_thompson5910/Algebra%20dot%20com/circle-1.png\">\r<BR>\n" );
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document.write( "From the diagram, we see that half of the length of the chord \"x\" is a leg of a triangle with another leg of 6 units and a hypotenuse of 10 units.\r<BR>\n" );
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document.write( "Since we can see that the triangle has legs of 6 and x with a hypotenuse of 10, we can use the Pythagorean theorem to find the unknown side.\r<BR>\n" );
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document.write( "Pythagorean theorem:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2%2Bb%5E2=c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2%2Bb%5E2=c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > where a and b are the legs of the triangle and c is the hypotenuse\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%5E2%2Bx%5E2=10%5E2 ALIGN=MIDDLE  ALT=\"6%5E2%2Bx%5E2=10%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >  Plug in a=6, b=x, and c=10. Now lets solve for x\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=36%2Bx%5E2=100 ALIGN=MIDDLE  ALT=\"36%2Bx%5E2=100\"   DISABLED_style= \"max-width:90%; height:auto;\" > Square each individual term\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=100-36 ALIGN=MIDDLE  ALT=\"x%5E2=100-36\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 36 from both sides\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=64 ALIGN=MIDDLE  ALT=\"x%5E2=64\"   DISABLED_style= \"max-width:90%; height:auto;\" > Combine like terms\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28x%5E2%29=sqrt%2864%29 ALIGN=MIDDLE  ALT=\"sqrt%28x%5E2%29=sqrt%2864%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the square root of both sides. Note: only the positive square root is considered.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=8 ALIGN=MIDDLE  ALT=\"x=8\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify the square root\r<BR>\n" );
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document.write( "Since the length of \"x\" is half of the length of the chord, this means that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A8=16 ALIGN=MIDDLE  ALT=\"2%2A8=16\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the length of the entire chord.\r<BR>\n" );
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document.write( "So the length of the chord is 16 units. </SPAN>\n" );
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