document.write( "Question 192950: If 31z5 is a multiple of 9, where z is a digit, what is the value of z? \n" ); document.write( "
Algebra.Com's Answer #144804 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If 31z5 is a multiple of 9 (where z is a single digit), then the digits MUST add to a number that is a multiple of 9 (hopefully, they will add to 9 itself).\r
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\n" ); document.write( "\n" ); document.write( "So the digits must add to 0, 9, 18, 27, 36, 45, 54, 63, 72, etc...\r
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\n" ); document.write( "\n" ); document.write( "So this gives us the equation:\r
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\n" ); document.write( "\n" ); document.write( "\"3%2B1%2Bz%2B5=9k\" where \"k\" is an integer (ie whole number)\r
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\n" ); document.write( "\n" ); document.write( "So if \"k=1\" (the smallest possible k value where we get a solution), then... \r
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\n" ); document.write( "\n" ); document.write( "\"3%2B1%2Bz%2B5=9\"\r
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\n" ); document.write( "\n" ); document.write( "Solve for \"z\" to get: \"z%2B9=9\" ---> \"z=0\"\r
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\n" ); document.write( "\n" ); document.write( "So when \"k=1\", then \"z=0\" giving the number 3105\r
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\n" ); document.write( "\n" ); document.write( "So 3105 is divisible by 9. Check: \"3105%2F9=345\" remainder 0.\r
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\n" ); document.write( "\n" ); document.write( "If \"k=2\", then... \r
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\n" ); document.write( "\n" ); document.write( "\"3%2B1%2Bz%2B5=18\"\r
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\n" ); document.write( "\n" ); document.write( "Solve for \"z\" to get: \"z%2B9=18\" ---> \"z=9\"\r
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\n" ); document.write( "\n" ); document.write( "So when \"k=1\", then \"z=9\" giving the number 3195\r
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\n" ); document.write( "\n" ); document.write( "So 3195 is divisible by 9. Check: \"3195%2F9=395\" remainder 0.\r
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\n" ); document.write( "\n" ); document.write( "If \"k=3\", then...\r
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\n" ); document.write( "\n" ); document.write( "\"3%2B1%2Bz%2B5=27\"\r
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\n" ); document.write( "\n" ); document.write( "Solve for \"z\" to get: \"z%2B9=27\" ---> \"z=18\"\r
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\n" ); document.write( "\n" ); document.write( "But since \"z\" is a single digit, this means that \"0%3C=z%3C=9\". So ANY value of \"k\" greater than 2 will give us a \"z\" value greater than 9. So this means that we're done looking for values of \"z\".\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the two values of \"z\" are 0 and 9 produce the multiples of 9 3105 and 3195 respectively.
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