document.write( "Question 192269: Q: There are 12 points in a plane of which 5 are collinear. The number of triangles is?\r
\n" ); document.write( "\n" ); document.write( "I think we have to combine C(5,2) (out of 5 collinear, 2 points can form a side of triangle) with the combination of the rest of the points... but i m not getting any answer out of the four options
\n" ); document.write( "a)200
\n" ); document.write( "b)211
\n" ); document.write( "c)210
\n" ); document.write( "d)none of these
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Algebra.Com's Answer #144800 by bhayzone(8)\"\" \"About 
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I think the answer is D - none of the above. I get a total of 105 triangles\r
\n" ); document.write( "\n" ); document.write( "I'm assuming coliner means they are on the same line.\r
\n" ); document.write( "\n" ); document.write( "5 points on the same line (assume they form one side of the triangle). So how many distinct 2 points (as two points constitue one side) can you select from a set of 5 points. Note side AB = Side BA so this is a combination problem.\r
\n" ); document.write( "\n" ); document.write( "5! div 2!*3! = 10 sides -------------- A\r
\n" ); document.write( "\n" ); document.write( "From the Remaining 7 points, how many triangles can you make. This is same as asking you to select 3 distinct points from 7. Again a combination problem as Triangle ABC = Triangle BAC\r
\n" ); document.write( "\n" ); document.write( "7! div 3!*4! = 35 -------------------- B\r
\n" ); document.write( "\n" ); document.write( "NOT DONE YET !!!
\n" ); document.write( "Each side in A can combile with each of the 7 points to make a triangle. Thus, 10 sides can make 70 triangles ----- C\r
\n" ); document.write( "\n" ); document.write( "Answer = C+B = 105
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