document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192772>Question 192772</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Show a complete solution to problem.<BR>\n" );
document.write( "Junior's boat will go 15 miles per hour in stillwater. If he can go 12 miles downstream in the same amount of time as it takes to go 9 miles upstream, then what is the speed of the current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144799 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144799\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d=st d=istance, s=speed, t=time<BR>\n" );
document.write( "t=d/s<BR>\n" );
document.write( "Let c=speed of current<BR>\n" );
document.write( "12/(15+c)=9/(15-c) time going downstream = time going upstream<BR>\n" );
document.write( "12(15-c)=9(15+c) multiply each side by the denominators to eliminate fractions.<BR>\n" );
document.write( "180-12c=135+9c<BR>\n" );
document.write( "-21c=-45<BR>\n" );
document.write( "c=15/7=2.14... mph speed of current<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
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