document.write( "Question 192905: A train traveling 50 mph left a station 30 minutes before a second train running at 55 mph. How soon did the second train overtake the first?\r
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document.write( "If 50x represents the distance the slower train travels, then the faster train travels \n" );
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Algebra.Com's Answer #144798 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A train traveling 50 mph left a station 30 minutes before a second train running at 55 mph. How soon did the second train overtake the first? \n" ); document.write( "--------------------------- \n" ); document.write( "1st train DATA: \n" ); document.write( "rate = 50 mph ; time = x hrs ; distance = rt = 50x miles \n" ); document.write( "------------------------------ \n" ); document.write( "2nd train DATA: \n" ); document.write( "rate = 55 mph ; time = (x-(1/2)) hrs ; distance = rt = 55(x-(1/2)) miles \n" ); document.write( "---------------------------- \n" ); document.write( "Equation: \n" ); document.write( "distance = distance \n" ); document.write( "50x = 55(x-(1/2) \n" ); document.write( "50x = 55x - (55/2) \n" ); document.write( "-5x = -55/2 \n" ); document.write( "x = 11/2 \n" ); document.write( "x = 5 1/2 hrs (time at which the 2nd train overtakes the 1st train) \n" ); document.write( "================================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |