document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192920>Question 192920</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.  Simplify and evaluate:<BR>\n" );
document.write( " Simplify and evaluate:<BR>\n" );
document.write( " (x3 y-4/5x6 y-8 z0)3<BR>\n" );
document.write( "x cubed y -4 / 5x to 6th power y -8 power.  I can't seem to show exponents correctly. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144779 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> restating  the  problem  as we  understand  it\r<BR>\n" );
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document.write( "(x^3 *y^(-4))/ ( (5x)^6 * y^(-8))\r<BR>\n" );
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document.write( "we  usually  look  at  coefficients,  x's  ,  and  y,  separately\r<BR>\n" );
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document.write( "coefficients,  1/(5^6)=1/15625\r<BR>\n" );
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document.write( "x's,  x^3/x^6=x^-3=1/x^3,  remember  to  divide  common  bases  subtract exponents, and a  negative  exponent  indicates  a  reciprocal.\r<BR>\n" );
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document.write( "y's,  y^(-4)/y^(-8)=  y^( (-4)-(-8))=y^4\r<BR>\n" );
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document.write( "combining  y^4/((15625)*(x^3))\r<BR>\n" );
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document.write( "to  check  let  x=2,y=3  arbitrarily\r<BR>\n" );
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document.write( "answer  is  3^4 /(15625*(2^3))=81/(15625*8)=.000648\r<BR>\n" );
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document.write( "original  is  ( 2^3*3^(-4)0/((5*2)^6 *3^(-8))=8(.0123)/(1000000*.0001524)=.0984/152.42=.000645 ok </SPAN>\n" );
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