document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192873>Question 192873</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joe has a collection of nickels and dimes that is worth $6.05. If the number of dimes was doubled and the number of nickels was decreased by 10, the value of the coins would be $9.85. How many dimes does he have?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144775 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144775\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Joe has a collection of nickels and dimes that is worth $6.05. If the number of dimes was doubled and the number of nickels was decreased by 10, the value of the coins would be $9.85. How many dimes does he have? <BR>\n" );
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document.write( "Value Equation: 5n + 10d = 605 cents<BR>\n" );
document.write( "Value Equation: 10(2d) + 5(n-10) = 985 cents<BR>\n" );
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document.write( "Modified Equations:<BR>\n" );
document.write( "20d + 5n = 1035 <BR>\n" );
document.write( "10d + 5n = 605<BR>\n" );
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document.write( "10d = 430<BR>\n" );
document.write( "d = 43 (# of dimes)<BR>\n" );
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document.write( "Substitute into 5n + 10d = 605 to solve for \"n\":<BR>\n" );
document.write( "5n + 10*43 = 605<BR>\n" );
document.write( "5n = 175<BR>\n" );
document.write( "n = 35 (# of nickels)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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