document.write( "Question 26622: Please explain the steps to solve the following problem:
\n" ); document.write( "y/4-y+5/3=0\r
\n" ); document.write( "\n" ); document.write( "i have changed the bottom numbers into a common denominator of 12 then tried to work through the equation with the following:
\n" ); document.write( "36y - 48y +5 = 0
\n" ); document.write( "12y + 5 = 0
\n" ); document.write( "12y +5 -5 = 0-5
\n" ); document.write( "12y= -5
\n" ); document.write( "12y/12= -5/12
\n" ); document.write( "y= -5/12\r
\n" ); document.write( "\n" ); document.write( "can you please explain where I have gone wrong. \n" ); document.write( "

Algebra.Com's Answer #14472 by longjonsilver(2297) $\"\"$ $\"About$

You can put this solution on YOUR website!
y/4 - y + 5/3 = 0 \r
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\n" ); document.write( "\n" ); document.write( "You do not need a denominator of 12... all you need do is get the terms with a y in them together. In this case, let their denominators be 4.\r
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\n" ); document.write( "\n" ); document.write( "y/4 - 4y/4 + 5/3 = 0
\n" ); document.write( "-3y/4 + 5/3 = 0
\n" ); document.write( "-3y/4 = -5/3
\n" ); document.write( "3y/4 = 5/3
\n" ); document.write( "--> y = 20/9\r
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\n" ); document.write( "\n" ); document.write( "jon.
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