document.write( "Question 26640: find the domain of the function
\n" ); document.write( "f(x)=x+6-(square root of x+2)
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\n" ); document.write( " 3x-1/2\r
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Algebra.Com's Answer #14467 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
to be honest, looking at the \"function\"... the existence of the square root means that the fundamental definition of what a function is may well be broken by this. In short, i do not believe this is a function, strictly.\r
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\n" ); document.write( "\n" ); document.write( "However, putting that aside! What values of x are we allowed to put into the equation? Well avoid anything that makes the square root negative is nothing less than x=-2. Also the denominator should not be zero: when it is, the equation will become infinite..an asymptote.\r
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\n" ); document.write( "\n" ); document.write( "This happens when 3x-(1/2) = 0
\n" ); document.write( "--> 3x = 1/2
\n" ); document.write( "--> x = 1/6\r
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\n" ); document.write( "\n" ); document.write( "So, at a first glance the domain is any real value of x greater or equal to -2 but not 1/6.\r
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\n" ); document.write( "\n" ); document.write( "Ask your teacher though to clarify if this is really a function! I think it isn't :-)\r
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\n" ); document.write( "\n" ); document.write( "jon.
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