document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26639>Question 26639</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I AM TRYING TO HELP MY DAUGHTER SOLVE THE FOLLOWING PROBLEM:<BR>\n" );
document.write( "x=3y<BR>\n" );
document.write( "3y-6=2x\r<BR>\n" );
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document.write( "Can you help me to explain how to solve this for her? Where do I begin?\r<BR>\n" );
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document.write( "Thanks, <BR>\n" );
document.write( "Jan </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14463 by </B><A HREF=/tutors/aboutme.mpl?userid=wuwei96815><B>wuwei96815(245)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wuwei96815><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14463\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are several ways to solve this problem.  Let's use the substitution method.  Since we know the value of x (x=3y), we can substitute this value in the second equation and solve for y. \r<BR>\n" );
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document.write( "3y-6=2x<BR>\n" );
document.write( "3y-6=2(3y)<BR>\n" );
document.write( "3y-6=6y<BR>\n" );
document.write( "-6=-3y+6y<BR>\n" );
document.write( "-6=3y<BR>\n" );
document.write( "-6/3=y<BR>\n" );
document.write( "-2=y\r<BR>\n" );
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document.write( "Now that we have the value for y we can go back and substitute this in either equation and solve for x.<BR>\n" );
document.write( "x=3y<BR>\n" );
document.write( "x=3(-2)<BR>\n" );
document.write( "x=-6\r<BR>\n" );
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document.write( "So, x=-6 and y=-2. </SPAN>\n" );
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