document.write( "Question 192566: Practical Application of Quadratic Equations \r
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document.write( "1.A rectangular garden has dimensions of 15 feet by 11 feet. A gravel path of uniform width is to be built around the garden. How wide can the path be if there is enough gravel for 192 square feet?
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document.write( "2.A business invests $8,000 in a savings account for two years. At the beginning of the second year, an additional $2,500 is invested. At the end of the second year, the account balance is $11,445. What was the annual interest rate? \r
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document.write( "3.Steve traveled 150 miles at a certain speed. Had he gone 20mph faster, the trip would have taken 2 hours less. Find the speed of his vehicle.
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document.write( " 4. The Hudson River flows at a rate of 5 miles per hour. A patrol boat travels 40 miles upriver, and returns in a total time of 6 hours. What is the speed of the boat in still water?\r
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Algebra.Com's Answer #144612 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 1.A rectangular garden has dimensions of 15 feet by 11 feet. A gravel path of uniform width is to be built around the garden. How wide can the path be if there is enough gravel for 192 square feet? \n" ); document.write( ": \n" ); document.write( "Let x = the width of the path \n" ); document.write( "then \n" ); document.write( "(2x+15) by (2x+11) = overall area of the garden and the path \n" ); document.write( "and FOIL this \n" ); document.write( "Overall Area = 4x^2 + 52x + 165 \n" ); document.write( ": \n" ); document.write( "Garden area: 15 * 11 = 165 \n" ); document.write( ": \n" ); document.write( "Overall area - garden area = path area (given as 192 sq/ft) \n" ); document.write( "(4x^2 + 52x + 165) - 165 = 192 \n" ); document.write( "4x^2 + 52x + 165 - 165 - 192 = 0 \n" ); document.write( "4x^2 + 52x - 192 = 0 \n" ); document.write( "Simplify, divide by 4 \n" ); document.write( "x^2 + 13x - 48 \n" ); document.write( "Factors to: \n" ); document.write( "(x + 16)(x - 3) = 0 \n" ); document.write( "Positive solution \n" ); document.write( "x = 3 ft is the width of the garden path \n" ); document.write( "Check \n" ); document.write( "(21*17) - (15*11) = \n" ); document.write( "357 - 165 = 192 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "2.A business invests $8,000 in a savings account for two years. At the beginning of the second year, an additional $2,500 is invested. At the end of the second year, the account balance is $11,445. What was the annual interest rate? \n" ); document.write( ": \n" ); document.write( "Let r = interest in decimal form \n" ); document.write( ": \n" ); document.write( "(x+1)(8000(x+1) + 2500) = 11445 \n" ); document.write( "(x+1)(8000x + 8000 + 2500) = 11445 \n" ); document.write( "(x+1)(8000x + 10500) = 11445 \n" ); document.write( "FOIL \n" ); document.write( "8000x^2 + 18500x + 10500 = 11445 \n" ); document.write( "8000x^2 + 18500x + 10500 - 11445 = 0 \n" ); document.write( "8000x^2 + 18500x - 945 \n" ); document.write( "Simplify divide by 5 \n" ); document.write( "1600x^2 + 3700x - 189 = 0 \n" ); document.write( "Solve this using the quadratic formula, \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "3.Steve traveled 150 miles at a certain speed. Had he gone 20mph faster, the trip would have taken 2 hours less. Find the speed of his vehicle. \n" ); document.write( ": \n" ); document.write( "Let s = \"that certain speed\" \n" ); document.write( "then \n" ); document.write( "(s+20) = the faster speed \n" ); document.write( ": \n" ); document.write( "Write a time equation: time = dist/speed \n" ); document.write( "Actual time = faster speed time + 2 hrs \n" ); document.write( " \n" ); document.write( "Solve this equation for s \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "4. The Hudson River flows at a rate of 5 miles per hour. A patrol boat travels 40 miles upriver, and returns in a total time of 6 hours. What is the speed of the boat in still water? \n" ); document.write( ": \n" ); document.write( "Let s = speed in still water \n" ); document.write( "then \n" ); document.write( "(s+5) = speed down stream \n" ); document.write( "(s-5) = speed up stream \n" ); document.write( ": \n" ); document.write( "time downstream + time upstream = 6 hrs \n" ); document.write( " \n" ); document.write( "Solve for s \n" ); document.write( " |