Algebra.Com's Answer #144595 by yuendatlo(23)  You can put this solution on YOUR website! first, isolate y so that you have a equation like this: \n" );
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document.write( " Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc | \n" );
document.write( "Equation describes a sloping line. For any \n" );
document.write( " equation ax+by+c = 0, slope is .- X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 3/3 = 1.
- Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 3/2 = 1.5.
- Slope is -3/2 = -1.5.
- Equation in slope-intercept form: y=-1.5*x+1.5.
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document.write( " Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc | \n" );
document.write( "Equation describes a sloping line. For any \n" );
document.write( " equation ax+by+c = 0, slope is .- X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 8/2 = 4.
- Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 8/3 = 2.66666666666667.
- Slope is -2/3 = -0.666666666666667.
- Equation in slope-intercept form: y=-0.666666666666667*x+2.66666666666667.
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document.write( "slope of 3x+2y=3 is -1.5, \n" );
document.write( "and slope of the other is -2/3 \n" );
document.write( "therefore, they are neither perpendicular, nor parallel.\r \n" );
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document.write( " Solved by pluggable solver: SOLVE linear system by SUBSTITUTION | \n" );
document.write( "Solve: \n" );
document.write( " We'll use substitution. After moving 4*y to the right, we get: \n" );
document.write( " , or . Substitute that \n" );
document.write( " into another equation: \n" );
document.write( " and simplify: So, we know that y=1.5. Since , x=1. \n" );
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document.write( " Answer: . \n" );
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