document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192580>Question 192580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let AB be a chord in a circle centered at O with radius r. For what point M on the arc AB the sum of the distances [AM]+[MB] is minimum. Find this distance in terms of the radius r and the distance d=[AB]. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144573 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144573\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "I really wonder whether you really meant to say \"the sum of the distances AM + BM is a <i>minimum,</i>\" because what you have formed is a triangle with sides <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\large \overline{AM},\ \overline{BM},\ \overline{AB}\">.  The Triangle Inequality tells us that AM + BM must always be greater than AB, unless, of course, M is coincident with either A or B such that you no longer have a triangle and AM + BM = 0 + d = d or AM + BM = d + 0 = d -- such being the minimum limiting case.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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