document.write( "Question 192446This question is from textbook Intermediate Algebra
\n" ); document.write( ": To solve percent mixture problems: \r
\n" ); document.write( "\n" ); document.write( "How many quarts of water must be added to 5 qt. of an 80% antifreeze solution to make a 50% antifreeze solution? \r
\n" ); document.write( "\n" ); document.write( "my try: \r
\n" ); document.write( "\n" ); document.write( "Water x 1.00 x
\n" ); document.write( "80% 75 .80 75(.80)
\n" ); document.write( "50% 75+x .50 .50(75+x)\r
\n" ); document.write( "\n" ); document.write( "x+75(80) =50(75+x)
\n" ); document.write( "x+6000=3750 + 50x
\n" ); document.write( "-49x = -2250
\n" ); document.write( "x = -45.91
\n" ); document.write( "????\r
\n" ); document.write( "\n" ); document.write( "Wrong?
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #144482 by Mathtut(3670) $\"\"$ $\"About$

You can put this solution on YOUR website!
the amount of antifreeze remains constant
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\n" ); document.write( ".8(5)=.5(5+x)
\n" ); document.write( ":
\n" ); document.write( "4=2.5+.5x
\n" ); document.write( ":
\n" ); document.write( ".5x=1.5
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\n" ); document.write( "x=3 quarts \n" ); document.write( "

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