document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=192315>Question 192315</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I have x(x+2)(x-5)<BR>\n" );
document.write( "would i really need to solve it to find the interval notation? isn't it (- infinity, -2) U (0,5)... ah I just see that 0,5 cannot be, if so it should be 5, infinity. hm... so do i solve x^2+2x (x-5) which is x^3-5x^2+2x^2-10x but how would I go from here? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #144479 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=144479\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^3-3x^2-10x<0<BR>\n" );
document.write( "-2, 0 and 5 are inflection points. We have to check on either side of inflection points to see if y is <0 or >0.<BR>\n" );
document.write( "if x=-3, then x^3-3x^2-10x=-24<BR>\n" );
document.write( "x=-1 then x^3-3x^2-10x=6<BR>\n" );
document.write( "x=2 then x^3-3x^2-10x=-24<BR>\n" );
document.write( "x=6 then x^3-3x^2-10x=48<BR>\n" );
document.write( "x(-infinity, -2)U(0,5)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( ".<BR>\n" );
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