document.write( "Question 192009This question is from textbook Elementary and intermediate algebra
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document.write( ": The ancient Greeks thought that the most pleasing shape for a rectangle was one for which has the ratio of the length to the width was approximately 8 to 5, the golden ratio. If the length of a rectangular painting is 2 ft longer than its width, then for what dimensions would the length and width have the golden ratio?\r
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Algebra.Com's Answer #144401 by jojo14344(1513)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "Golden Ratio: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And the painting, \n" ); document.write( "Substitute this \"L\" to our Golden Ratio:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Cross multiply, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let us check on our Golden Ratio: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Reduce left term by dividing both num.&den. by \"2\": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thank you, \n" ); document.write( "Jojo \n" ); document.write( " \n" ); document.write( " |